JEE Main 2022 · 25 Jul · Shift 1 · Mathematics Q16

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MathematicsSingle correct+4 / -1Question 16 of 90

If the sum and the product of mean and variance of a binomial distribution are 24 and 128 respectively, then the probability of one or two successes is :

\dfrac{33}{2^{32}}

\dfrac{33}{2^{29}}

\dfrac{33}{2^{28}}

\dfrac{33}{2^{27}}

Answer and worked solution

Official answer: C

Mean and variance 16 and 8: $q=\frac12$ , $n=32$ .

Probability. $\frac{32+496}{2^{32}}=\frac{33}{2^{28}}$ .

(C)

Topics:Binomial distribution

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JEE Main 2022 · 25 Jul · Shift 1, Mathematics question 16