JEE Main 2022 · 30 Jun · Shift 1 · Physics Q50

PhysicsSingle correct+4 / -1Question 50 of 90

A hydrogen atom in ground state absorbs 12.09 eV of energy. The orbital angular momentum of the electron is increased by :

1.05\times10^{-34}

2.11\times10^{-34}

3.16\times10^{-34}

4.22\times10^{-34}

Answer and worked solution

Official answer: B

12.09 eV lifts the electron from $n=1$ to $n=3$ ; $L$ rises by $\frac{2h}{2\pi}\approx2.11\times10^{-34}$ J s.

(B)

Topics:Bohr model and hydrogen spectrum

JEE Main 2022 · 30 Jun · Shift 1, Physics question 50