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← JEE Main 2022 · 30 Jun · Shift 1
PhysicsSingle correct+4 / -1Question 41 of 90

JEE Main 2022 · 30 Jun · Shift 1, Physics question 41

A sample of monoatomic gas is taken at initial pressure of 75 kPa. The volume of the gas is then compressed from 1200 cm3^3 to 150 cm3^3 adiabatically. In this process, the value of workdone on the gas will be :

Choose one option
Answer and worked solution

Official answer: B

Final pressure. 75×85/3=240075\times8^{5/3}=2400 kPa.

Work on gas. P2V2−P1V1γ−1=360−902/3=405\dfrac{P_2V_2-P_1V_1}{\gamma-1}=\dfrac{360-90}{2/3}=405 J.

(B)