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← JEE Main 2022 · 30 Jun · Shift 1
ChemistryInteger+4 / -1Question 89 of 90

JEE Main 2022 · 30 Jun · Shift 1, Chemistry question 89

A hydrocarbon 'X' is found to have molar mass of 80. A 10.0 mg of compound 'X' on hydrogenation consumed 8.40 mL of H2\mathrm{H_2} gas (measured at STP). Ozonolysis of compound 'X' yields only formaldehyde and dialdehyde. The total number of fragments/molecules produced from the ozonolysis of compound 'X' is ______.

Answer and worked solution

Official answer: 4

Formula. M = 80 is C6H8\mathrm{C_6H_8}; 8.4022400÷0.01080=3\frac{8.40}{22400}\div\frac{0.010}{80}=3 C=C.

X is hexa-1,3,5-triene; ozonolysis gives 2 HCHO and 2 glyoxal: 4 molecules.

Answer: 4

Topics:Alkenes