JEE Main 2022 · 30 Jun · Shift 1 · Chemistry Q71

ChemistrySingle correct+4 / -1Question 71 of 90

Correct formula of the compound which gives a white precipitate with $\mathrm{BaCl_2}$ solution, but not with $\mathrm{AgNO_3}$ solution, is

\mathrm{[Co(NH_3)_5Br]SO_4}

\mathrm{[Co(NH_3)_5SO_4]Br}

\mathrm{[Pt(NH_3)_4Cl_2]Br_2}

\mathrm{[Pt(NH_3)_4Br_2]Cl_2}

Answer and worked solution

Official answer: A

Ionisable sulfate, bromide bound: $\mathrm{[Co(NH_3)_5Br]SO_4}$ gives $\mathrm{BaSO_4}$ but no AgBr.

(A)

Topics:Isomerism in complexes Anion analysis

JEE Main 2022 · 30 Jun · Shift 1, Chemistry question 71