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← JEE Main 2022 · 29 Jun · Shift 2
PhysicsInteger+4 / -1Question 53 of 90

JEE Main 2022 · 29 Jun · Shift 2, Physics question 53

In an experiment to determine the velocity of sound in air at room temperature using a resonance tube, the first resonance is observed when the air column has a length of 20.0 cm for a tuning fork of frequency 400 Hz is used. The velocity of the sound at room temperature is 336 ms−1^{-1}. The third resonance is observed when the air column has a length of ______ cm

Answer and worked solution

Official answer: 104

Wavelength 336400=84\frac{336}{400}=84 cm. First resonance λ4−e=20\frac\lambda4-e=20 gives e=1e=1 cm.

Third resonance. 5λ4−e=105−1=104\frac{5\lambda}4-e=105-1=104 cm.

Answer: 104