JEE Main 2022 · 29 Jun · Shift 2 · Physics Q42

PhysicsSingle correct+4 / -1Question 42 of 90

The motion of a simple pendulum executing S.H.M. is represented by the following equation.

$y=A\sin(\pi t+\phi)$ , where time is measured in second.

The length of pendulum is

97.23 cm

25.3 cm

99.4 cm

406.1 cm

Answer and worked solution

Official answer: C

Period $\frac{2\pi}\pi=2$ s, so $L=\dfrac{gT^2}{4\pi^2}=\dfrac g{\pi^2}\approx0.994$ m $=99.4$ cm.

(C)

Topics:Simple and compound pendulum

JEE Main 2022 · 29 Jun · Shift 2, Physics question 42