JEE Main 2022 · 29 Jun · Shift 2 · Physics Q38

← JEE Main 2022 · 29 Jun · Shift 2

PhysicsSingle correct+4 / -1Question 38 of 90

Starting with the same initial conditions, an ideal gas expands from volume $V_1$ to $V_2$ in three different ways. The work done by the gas is $W_1$ if the process is purely isothermal, $W_2$ , if the process is purely adiabatic and $W_3$ if the process is purely isobaric. Then, choose the correct option

W_1<W_2<W_3

W_2<W_3<W_1

W_3<W_1<W_2

W_2<W_1<W_3

Answer and worked solution

Official answer: D

On a p-V diagram from the same start, the isobar lies highest and the adiabat lowest: $W_2<W_1<W_3$ .

(D)

Topics:Work done by a gas Thermodynamic processes

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JEE Main 2022 · 29 Jun · Shift 2, Physics question 38