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← JEE Main 2022 · 29 Jun · Shift 2
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JEE Main 2022 · 29 Jun · Shift 2, Physics question 32

At what temperature a gold ring of diameter 6.230 cm be heated so that it can be fitted on a wooden bangle of diameter 6.241 cm ? Both the diameters have been measured at room temperature (27°C).

(Given: coefficient of linear thermal expansion of gold αL=1.4×10−5\alpha_L=1.4\times10^{-5} K−1^{-1})

Choose one option
Answer and worked solution

Official answer: D

Expansion. ΔT=ΔDDα=0.0116.230×1.4×10−5≈126\Delta T=\dfrac{\Delta D}{D\alpha}=\dfrac{0.011}{6.230\times1.4\times10^{-5}}\approx126 K.

Temperature 27+126≈15327+126\approx153 °C, closest to 152.7 °C.

(D)