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← JEE Main 2022 · 29 Jun · Shift 2
MathematicsInteger+4 / -1Question 29 of 90

JEE Main 2022 · 29 Jun · Shift 2, Mathematics question 29

Let M=[0−αα0]M=\begin{bmatrix}0&-\alpha\\\alpha&0\end{bmatrix}, where α\alpha is a non-zero real number an N=∑k=149M2kN=\displaystyle\sum_{k=1}^{49}M^{2k}. If (I−M2)N=−2I\left(I-M^2\right)N=-2I, then the positive integral value of α\alpha is ______.

Answer and worked solution

Official answer: 1

Square. M2=−α2IM^2=-\alpha^2I, so N=∑k=149(−α2)kIN=\sum_{k=1}^{49}(-\alpha^2)^kI and (1+α2)N=−2I(1+\alpha^2)N=-2I.

Try α=1\alpha=1. ∑k=149(−1)k=−1\sum_{k=1}^{49}(-1)^k=-1, and 2⋅(−1)=−22\cdot(-1)=-2.

Answer: 1