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← JEE Main 2022 · 29 Jun · Shift 2
MathematicsInteger+4 / -1Question 22 of 90

JEE Main 2022 · 29 Jun · Shift 2, Mathematics question 22

Let y=y(x)y=y(x), x>1x>1, be the solution of the differential equation (x−1)dydx+2xy=1x−1(x-1)\dfrac{dy}{dx}+2xy=\dfrac1{x-1}, with y(2)=1+e42e4y(2)=\dfrac{1+e^4}{2e^4}. If y(3)=eα+1βeαy(3)=\dfrac{e^\alpha+1}{\beta e^\alpha}, then the value of α+β\alpha+\beta is equal to ______.

Answer and worked solution

Official answer: 14

Linear. y′+2xx−1y=1(x−1)2y'+\dfrac{2x}{x-1}y=\dfrac1{(x-1)^2}; integrating factor e2x(x−1)2e^{2x}(x-1)^2.

Integrate. ye2x(x−1)2=e2x2+Cye^{2x}(x-1)^2=\frac{e^{2x}}2+C; y(2)y(2) gives C=12C=\frac12.

At 3. y=e6+18e6y=\dfrac{e^6+1}{8e^6}: α=6\alpha=6, β=8\beta=8.

Answer: 14