JEE Main 2022 · 29 Jun · Shift 1 · Physics Q46

← JEE Main 2022 · 29 Jun · Shift 1

PhysicsSingle correct+4 / -1Question 46 of 90

A longitudinal wave is represented by $x=10\sin2\pi\left(nt-\dfrac x\lambda\right)$ cm. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to :

2\pi

5\pi

\pi

\dfrac{5\pi}2

Answer and worked solution

Official answer: B

Speeds. Maximum particle speed $2\pi n\times10$ ; wave speed $n\lambda$ . $20\pi n=4n\lambda$ gives $\lambda=5\pi$ .

(B)

Topics:Wave equation and progressive waves

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JEE Main 2022 · 29 Jun · Shift 1, Physics question 46