JEE Main 2022 · 29 Jun · Shift 1 · Mathematics Q8

MathematicsSingle correct+4 / -1Question 8 of 90

Let $\alpha$ and $\beta$ be the roots of the equation $x^2+(2i-1)=0$ . Then, the value of $\left|\alpha^8+\beta^8\right|$ is equal to :

250

1250

1500

Answer and worked solution

Official answer: A

Roots. $\alpha^2=\beta^2=1-2i$ , so $\alpha^8+\beta^8=2(1-2i)^4$ .

Modulus. $2\cdot|1-2i|^4=2\cdot25=50$ .

(A)

Topics:Modulus and argument Algebra of complex numbers

JEE Main 2022 · 29 Jun · Shift 1, Mathematics question 8