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← JEE Main 2022 · 28 Jun · Shift 2
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JEE Main 2022 · 28 Jun · Shift 2, Physics question 58

A liquid of density 750 kgm−3^{-3} flows smoothly through a horizontal pipe that tapers in cross-sectional area from A1=1.2×10−2A_1=1.2\times10^{-2}m2^2 to A2=A12A_2=\dfrac{A_1}2. The pressure difference between the wide and narrow sections of the pipe is 4500 Pa. The rate of flow of liquid is ______ ×10−3\times10^{-3} m3^3s−1^{-1}.

Answer and worked solution

Official answer: 24

Continuity. v2=2v1v_2=2v_1. Bernoulli. 4500=12⋅750⋅3v124500=\frac12\cdot750\cdot3v_1^2, so v1=2v_1=2 m s−1^{-1}.

Flow. 1.2×10−2×2=24×10−31.2\times10^{-2}\times2=24\times10^{-3} m3^3 s−1^{-1}.

Answer: 24

Topics:Bernoulli's principleContinuity equation
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