JEE Main 2022 · 28 Jun · Shift 2 · Physics Q46

← JEE Main 2022 · 28 Jun · Shift 2

PhysicsSingle correct+4 / -1Question 46 of 90

In young's double slit experiment performed using a monochromatic light of wavelength $\lambda$ , when a glass plate ( $\mu=1.5$ ) of thickness $x\lambda$ is introduced in the path of the one of the interfering beams, the intensity at the position where the central maximum occurred previously remains unchanged. The value of $x$ will be :

1.5

0.5

Answer and worked solution

Official answer: B

Unchanged intensity needs the extra path to be a whole number of wavelengths: $(\mu-1)x\lambda=\lambda$ , so $x=2$ for the smallest plate.

(B)

Topics:Interference and Young's double slit

← Previous question Next question →

JEE Main 2022 · 28 Jun · Shift 2, Physics question 46