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← JEE Main 2022 · 28 Jun · Shift 2
PhysicsSingle correct+4 / -1Question 41 of 90

JEE Main 2022 · 28 Jun · Shift 2, Physics question 41

Resistance of the wire is measured as 2 Ω\Omega and 3 Ω\Omega at 10°C and 30°C respectively. Temperature co-efficient of resistance of the material of the wire is :

Choose one option
Answer and worked solution

Official answer: A

R=R0(1+αT)R=R_0(1+\alpha T). 32=1+30α1+10α\dfrac{3}{2}=\dfrac{1+30\alpha}{1+10\alpha} gives α=130≈0.033\alpha=\frac1{30}\approx0.033 °C−1^{-1}.

(A)