Skip to content
dronacharya.ai
← JEE Main 2022 · 28 Jun · Shift 2
MathematicsInteger+4 / -1Question 24 of 90

JEE Main 2022 · 28 Jun · Shift 2, Mathematics question 24

If lim⁡x→1sin⁡(3x2−4x+1)−x2+12x3−7x2+ax+b=−2\displaystyle\lim_{x\to1}\frac{\sin\left(3x^2-4x+1\right)-x^2+1}{2x^3-7x^2+ax+b}=-2, then the value of (a−b)(a-b) is equal to ______.

Answer and worked solution

Official answer: 11

0/0 twice. The numerator and its derivative vanish at x=1x=1, so the denominator must too: a+b=5a+b=5 and 6−14+a=06-14+a=0, giving a=8a=8, b=−3b=-3.

Check. Second derivatives: numerator 6−2=46-2=4, denominator −2-2, limit −2-2.

a−b=11a-b=11.

Answer: 11