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← JEE Main 2022 · 28 Jun · Shift 2
MathematicsSingle correct+4 / -1Question 20 of 90

JEE Main 2022 · 28 Jun · Shift 2, Mathematics question 20

If cot⁡α=1\cot\alpha=1 and sec⁡β=−53\sec\beta=-\dfrac53, where π<α<3π2\pi<\alpha<\dfrac{3\pi}2 and π2<β<π\dfrac\pi2<\beta<\pi, then the value of tan⁡(α+β)\tan(\alpha+\beta) and the quadrant in which α+β\alpha+\beta lies, respectively are :

Choose one option
Answer and worked solution

Official answer: A

Values. tan⁡α=1\tan\alpha=1 (α=225°\alpha=225°); cos⁡β=−35\cos\beta=-\frac35, tan⁡β=−43\tan\beta=-\frac43 (β≈126.9°\beta\approx126.9°).

Sum. tan⁡(α+β)=1−431+43=−17\tan(\alpha+\beta)=\dfrac{1-\frac43}{1+\frac43}=-\frac17, and α+β≈351.9°\alpha+\beta\approx351.9°: fourth quadrant.

(A)