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← JEE Main 2022 · 28 Jun · Shift 2
ChemistryInteger+4 / -1Question 90 of 90

JEE Main 2022 · 28 Jun · Shift 2, Chemistry question 90

0.01 M KMnO4\mathrm{KMnO_4} solution was added to 20.0 mL of 0.05 M Mohr's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO4\mathrm{KMnO_4} solution left in the burette after the end point is ______ mL. (nearest integer)

Answer and worked solution

Official answer: 30

Equivalents. Fe2+\mathrm{Fe^{2+}}: 20×0.05=120\times0.05=1 mmol needs 15\frac15 mmol MnO4−\mathrm{MnO_4^-} = 20 mL of 0.01 M.

Left in the burette 50−20=3050-20=30 mL.

Answer: 30