JEE Main 2022 · 28 Jun · Shift 2, Chemistry question 84

For the given reactions

$$\mathrm{Sn^{2+}+2e^-\rightarrow Sn}$$
$$\mathrm{Sn^{4+}+4e^-\rightarrow Sn}$$

the electrode potentials are ; $E^\circ_{\mathrm{Sn^{2+}/Sn}}=-0.140$ V and $E^\circ_{\mathrm{Sn^{4+}/Sn}}=0.010$ V. The magnitude of standard electrode potential for $\mathrm{Sn^{4+}/Sn^{2+}}$ i.e. $E^\circ_{\mathrm{Sn^{4+}/Sn^{2+}}}$ is ______ $\times10^{-2}$ V. (Nearest integer)