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← JEE Main 2022 · 28 Jun · Shift 2
ChemistryInteger+4 / -1Question 81 of 90

JEE Main 2022 · 28 Jun · Shift 2, Chemistry question 81

100 g of an ideal gas is kept in a cylinder of 416 L volume at 27°C under 1.5 bar pressure. The molar mass of the gas is ______ g mol−1^{-1}. (Nearest integer)

(Given : R = 0.083 L bar K−1^{-1} mol−1^{-1})

Answer and worked solution

Official answer: 4

Molar mass. M=mRTPV=100×0.083×3001.5×416≈3.99M=\dfrac{mRT}{PV}=\dfrac{100\times0.083\times300}{1.5\times416}\approx3.99, i.e. 4 g mol−1^{-1}.

Answer: 4