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JEE Main 2022 · 28 Jun · Shift 1, Physics question 59

A singly ionized magnesium atom (A=24) ion is accelerated to kinetic energy 5 keV, and is projected perpendicularly into a magnetic field B of the magnitude 0.5 T. The radius of path formed will be ______ cm.

Answer and worked solution

Official answer: 10

Radius. r=2mKqBr=\dfrac{\sqrt{2mK}}{qB} with m=24×1.67×10−27m=24\times1.67\times10^{-27} kg, K=8×10−16K=8\times10^{-16} J:
r=2×4.0×10−26×8×10−161.6×10−19×0.5≈0.10 m=10 cm.r=\frac{\sqrt{2\times4.0\times10^{-26}\times8\times10^{-16}}}{1.6\times10^{-19}\times0.5}\approx0.10\text{ m}=10\text{ cm}.

Answer: 10

Topics:Motion in magnetic and electric fields
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