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JEE Main 2022 · 28 Jun · Shift 1, Physics question 57

A hanging mass M is connected to a four times bigger mass by using a string-pulley arrangement, as shown in the figure. The bigger mass is placed on a horizontal ice-slab and being pulled by 2 Mg force. In this situation, tension in the string is x5\frac x5 Mg for x = ______. Neglect mass of the string and friction of the block (bigger mass) with ice slab.

(Given g = acceleration due to gravity)

Block 4M on a horizontal ice slab pulled to the left by a force 2Mg; a string from the block passes over a pulley at the right edge to a hanging mass M.
Answer and worked solution

Official answer: 6

Acceleration. Net force on the system 2Mg−Mg2Mg-Mg over mass 5M5M: a=g5a=\frac g5, with M moving up.

Tension. T−Mg=Mg5T-Mg=\frac{Mg}5, so T=65MgT=\frac65Mg.

Answer: 6

Topics:Constraint motion and pulleysNewton's laws
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