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← JEE Main 2022 · 28 Jun · Shift 1
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JEE Main 2022 · 28 Jun · Shift 1, Physics question 55

The position vector of 1 kg object is r⃗=(3i^−j^)\vec r=\left(3\hat i-\hat j\right) m and its velocity v⃗=(3j^+k^)\vec v=\left(3\hat j+\hat k\right) ms−1^{-1}. The magnitude of its angular momentum is x\sqrt x Nm where xx is ______.

Answer and worked solution

Official answer: 91

Angular momentum. L⃗=m r⃗×v⃗=(3,−1,0)×(0,3,1)=(−1,−3,9)\vec L=m\,\vec r\times\vec v=(3,-1,0)\times(0,3,1)=(-1,-3,9).

Magnitude. 1+9+81=91\sqrt{1+9+81}=\sqrt{91}.

Answer: 91