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← JEE Main 2022 · 28 Jun · Shift 1
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JEE Main 2022 · 28 Jun · Shift 1, Physics question 50

The velocity of sound in a gas, in which two wavelengths 4.08m and 4.16m produce 40 beats in 12s, will be :

Choose one option
Answer and worked solution

Official answer: D

Beat frequency. 4012=103\frac{40}{12}=\frac{10}3 Hz.

Speed. v(14.08−14.16)=103v\left(\dfrac1{4.08}-\dfrac1{4.16}\right)=\dfrac{10}3, so v=103⋅4.08×4.160.08≈707.2v=\dfrac{10}3\cdot\dfrac{4.08\times4.16}{0.08}\approx707.2 m s−1^{-1}.

(D)

Topics:Beats