JEE Main 2022 · 28 Jun · Shift 1 · Physics Q44

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PhysicsSingle correct+4 / -1Question 44 of 90

The de Broglie wavelengths for an electron and a photon are $\lambda_e$ and $\lambda_p$ respectively. For the same kinetic energy of electron and photon, which of the following presents the correct relation between the de Broglie wavelengths of two ?

\lambda_p\propto\lambda_e^2

\lambda_p\propto\lambda_e

\lambda_p\propto\sqrt{\lambda_e}

\lambda_p\propto\sqrt{\dfrac1{\lambda_e}}

Answer and worked solution

Official answer: A

Electron. $\lambda_e=\dfrac h{\sqrt{2mK}}\propto K^{-1/2}$ . Photon. $\lambda_p=\dfrac{hc}K\propto K^{-1}$ .

So $\lambda_p\propto\lambda_e^2$ .

(A)

Topics:de Broglie waves

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JEE Main 2022 · 28 Jun · Shift 1, Physics question 44