Let R1R_1R1 and R2R_2R2 be relations on the set {1,2,…,50}\{1,2,\dots,50\}{1,2,…,50} such that
R1={(p,pn):p is a prime and n≥0 is an integer}R_1=\left\{\left(p,p^n\right):p\text{ is a prime and }n\ge0\text{ is an integer}\right\}R1={(p,pn):p is a prime and n≥0 is an integer} and
R2={(p,pn):p is a prime and n=0 or 1}R_2=\left\{\left(p,p^n\right):p\text{ is a prime and }n=0\text{ or }1\right\}R2={(p,pn):p is a prime and n=0 or 1}.
Then, the number of elements in R1−R2R_1-R_2R1−R2 is ______.
Official answer: 8
R1−R2R_1-R_2R1−R2 holds (p,pn)(p,p^n)(p,pn) with n≥2n\ge2n≥2 and pn≤50p^n\le50pn≤50: 4,8,16,324,8,16,324,8,16,32; 9,279,279,27; 252525; 494949.
Answer: 8