JEE Main 2022 · 28 Jun · Shift 1 · Mathematics Q18

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MathematicsSingle correct+4 / -1Question 18 of 90

The probability, that in a randomly selected 3-digit number at least two digits are odd, is

\dfrac{19}{36}

\dfrac{15}{36}

\dfrac{13}{36}

\dfrac{23}{36}

Answer and worked solution

Official answer: A

Count. Hundreds digit: 5 odd, 4 even choices; the others 5 and 5.
All three odd: 125. Hundreds odd and exactly one other odd: $5\cdot2\cdot25=250$ . Hundreds even, other two odd: $4\cdot25=100$ .

Probability. $\dfrac{475}{900}=\dfrac{19}{36}$ .

(A)

Topics:Classical probability Fundamental principle of counting

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JEE Main 2022 · 28 Jun · Shift 1, Mathematics question 18