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← JEE Main 2022 · 28 Jun · Shift 1
MathematicsSingle correct+4 / -1Question 4 of 90

JEE Main 2022 · 28 Jun · Shift 1, Mathematics question 4

Let AA be a matrix of order 3×33\times3 and det⁡(A)=2\det(A)=2. Then det⁡(det⁡(A)adj⁡(5adj⁡(A3)))\det\left(\det(A)\operatorname{adj}\left(5\operatorname{adj}\left(A^3\right)\right)\right) is equal to ______.

Choose one option
Answer and worked solution

Official answer: A

Rules for 3×33\times3. adj⁡(kM)=k2adj⁡M\operatorname{adj}(kM)=k^2\operatorname{adj}M and ∣adj⁡(adj⁡B)∣=∣B∣4|\operatorname{adj}(\operatorname{adj}B)|=|B|^4.

So ∣adj⁡(5adj⁡A3)∣=253⋅∣A3∣4=15625⋅84|\operatorname{adj}(5\operatorname{adj}A^3)|=25^3\cdot|A^3|^4=15625\cdot8^4, and multiplying by ∣A∣=2|A|=2 gives a factor 232^3:
8⋅15625⋅4096=512×106.8\cdot15625\cdot4096=512\times10^6.

(A)