JEE Main 2022 · 27 Jun · Shift 2 · Physics Q60

PhysicsInteger+4 / -1Question 60 of 90

The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resister of 40 $\Omega$ is ______ mA.

Your answer

Answer and worked solution

Official answer: 4

Conducting branch. One diode is forward biased; the other blocks.

Current. $\dfrac{1-0.6}{60+40}=4$ mA.

Answer: 4

JEE Main 2022 · 27 Jun · Shift 2, Physics question 60