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← JEE Main 2022 · 27 Jun · Shift 2
PhysicsInteger+4 / -1Question 57 of 90

JEE Main 2022 · 27 Jun · Shift 2, Physics question 57

In the given circuit 'a' is an arbitrary constant. The value of mm for which the equivalent circuit resistance is minimum, will be x2\sqrt{\dfrac x2}. The value of xx is ______.

A battery V in series with two groups: three resistors of value ma in parallel, followed by two resistors of value a/m in parallel.
Answer and worked solution

Official answer: 3

Resistance. R=ma3+a2mR=\dfrac{ma}3+\dfrac a{2m}, least when the terms are equal: m2=32m^2=\frac32, so m=32m=\sqrt{\frac32} and x=3x=3.

Answer: 3