JEE Main 2022 · 27 Jun · Shift 2 · Physics Q54

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PhysicsInteger+4 / -1Question 54 of 90

A particle executes simple harmonic motion. Its amplitude is 8 cm and time period is 6 s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is ______ s.

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Answer and worked solution

Official answer: 1

Extreme to half amplitude. $\cos\omega t=\frac12$ , so $t=\frac T6=1$ s.

Answer: 1

Topics:Simple harmonic motion

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JEE Main 2022 · 27 Jun · Shift 2, Physics question 54