JEE Main 2022 · 27 Jun · Shift 2, Physics question 51

A mass of 10 kg is suspended vertically by a rope of length 5 m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is $\theta=\tan^{-1}\left(x\times10^{-1}\right)$. The value of $x$ is ______.

(Given, $g=10$ m/s$^2$)