JEE Main 2022 · 27 Jun · Shift 2, Physics question 48

Given below are two statements:

Statement I: In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit ($E_1$) to higher energy orbit ($E_2$), is given as $hf=E_1-E_2$

Statement II: The jumping of electron from higher energy orbit ($E_2$) to lower energy orbit ($E_1$) is associated with frequency of radiation given as $f=(E_2-E_1)/h$

This condition is Bohr's frequency condition.

In the light of the above statements, choose the correct answer from the options given below: