Let S={1,2,3,4,5,6,7,8,9,10}S=\{1,2,3,4,5,6,7,8,9,10\}S={1,2,3,4,5,6,7,8,9,10}. Define f:S→Sf:S\to Sf:S→S asf(n)={2n,if n=1,2,3,4,52n−11,if n=6,7,8,9,10f(n)=\begin{cases}2n, & \text{if } n=1,2,3,4,5\\2n-11, & \text{if } n=6,7,8,9,10\end{cases}f(n)={2n,2n−11,if n=1,2,3,4,5if n=6,7,8,9,10Let g:S→Sg:S\to Sg:S→S be a function such that f∘g(n)={n+1,if n is oddn−1,if n is evenf\circ g(n)=\begin{cases}n+1, & \text{if } n \text{ is odd}\\n-1, & \text{if } n \text{ is even}\end{cases}f∘g(n)={n+1,n−1,if n is oddif n is even.
Then g(10)(g(1)+g(2)+g(3)+g(4)+g(5))g(10)\left(g(1)+g(2)+g(3)+g(4)+g(5)\right)g(10)(g(1)+g(2)+g(3)+g(4)+g(5)) is equal to ______.
Official answer: 190
Values of f. f=2,4,6,8,10,1,3,5,7,9f=2,4,6,8,10,1,3,5,7,9f=2,4,6,8,10,1,3,5,7,9 for n=1,…,10n=1,\dots,10n=1,…,10.
Find g. f(g(n))f(g(n))f(g(n)) is n+1n+1n+1 (odd nnn) or n−1n-1n−1 (even nnn): g(1)=1g(1)=1g(1)=1, g(2)=6g(2)=6g(2)=6, g(3)=2g(3)=2g(3)=2, g(4)=7g(4)=7g(4)=7, g(5)=3g(5)=3g(5)=3, g(10)=10g(10)=10g(10)=10.
Value. 10(1+6+2+7+3)=19010(1+6+2+7+3)=19010(1+6+2+7+3)=190.
Answer: 190