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← JEE Main 2022 · 27 Jun · Shift 2
MathematicsSingle correct+4 / -1Question 9 of 90

JEE Main 2022 · 27 Jun · Shift 2, Mathematics question 9

The integral ∫0117[1x]dx\displaystyle\int_0^1\frac1{7^{\left[\frac1x\right]}}dx, where [⋅][\cdot] denotes the greatest integer function, is equal to

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Answer and worked solution

Official answer: A

Split. On (1n+1,1n]\left(\frac1{n+1},\frac1n\right], [1x]=n\left[\frac1x\right]=n: I=∑n≥17−n(1n−1n+1)I=\displaystyle\sum_{n\ge1}7^{-n}\left(\frac1n-\frac1{n+1}\right).

Sums. ∑7−nn=ln⁡76\sum\frac{7^{-n}}n=\ln\frac76 and ∑7−nn+1=7(ln⁡76−17)\sum\frac{7^{-n}}{n+1}=7\left(\ln\frac76-\frac17\right).

Value. I=1−6ln⁡76=1+6log⁡e67I=1-6\ln\frac76=1+6\log_e\frac67.

(A)