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← JEE Main 2022 · 27 Jun · Shift 2
MathematicsSingle correct+4 / -1Question 4 of 90

JEE Main 2022 · 27 Jun · Shift 2, Mathematics question 4

Let AA and BB be two 3×33\times3 matrices such that AB=IAB=I and ∣A∣=18|A|=\dfrac18. Then ∣adj⁡(Badj⁡(2A))∣|\operatorname{adj}(B\operatorname{adj}(2A))| is equal to

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Answer and worked solution

Official answer: C

Determinants. B=A−1B=A^{-1}, so ∣B∣=8|B|=8. ∣adj⁡(2A)∣=∣2A∣2=(8⋅18)2=1|\operatorname{adj}(2A)|=|2A|^2=(8\cdot\frac18)^2=1.

Product. ∣Badj⁡(2A)∣=8|B\operatorname{adj}(2A)|=8, and ∣adj⁡M∣=∣M∣2=64|\operatorname{adj}M|=|M|^2=64.

(C)