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← JEE Main 2022 · 27 Jun · Shift 2
ChemistryInteger+4 / -1Question 89 of 90

JEE Main 2022 · 27 Jun · Shift 2, Chemistry question 89

If the initial pressure of a gas is 0.03 atm, the mass of the gas adsorbed per gram of the adsorbent is ______ ×10−2\times10^{-2} g.

Freundlich plot of log(x/m) against log p: a straight line of slope 1 with intercept 0.602 on the log(x/m) axis.
Answer and worked solution

Official answer: 12

Freundlich line. Slope 1 means 1n=1\frac1n=1; intercept log⁡k=0.602\log k=0.602, so k=4k=4.

Amount. xm=4×0.03=0.12\dfrac xm=4\times0.03=0.12 g =12×10−2=12\times10^{-2} g.

Answer: 12

Topics:Adsorption