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← JEE Main 2022 · 27 Jun · Shift 2
ChemistryInteger+4 / -1Question 87 of 90

JEE Main 2022 · 27 Jun · Shift 2, Chemistry question 87

For the reaction taking place in the cell:
Pt(s)∣H2(g)∣H+(aq) ∣∣ Ag+(aq)∣Ag(s)\mathrm{Pt(s)|H_2(g)|H^+(aq)\,||\,Ag^+(aq)|Ag(s)}
Ecell∘=+0.5332E^\circ_{\rm cell}=+0.5332 V.

The value of ΔfG⊖\Delta_fG^\ominus is ______ kJ mol−1^{-1}. (in nearest integer)

Answer and worked solution

Official answer: 51

Cell reaction. 12H2+Ag+→H++Ag\mathrm{\frac12H_2+Ag^+\rightarrow H^++Ag}, n=1n=1: ΔG°=−96500×0.5332≈−51.5\Delta G°=-96500\times0.5332\approx-51.5 kJ.

Formation of Ag+\mathrm{Ag^+}. All other species have ΔfG°=0\Delta_fG°=0, so ΔfG°(Ag+)=+51\Delta_fG°(\mathrm{Ag^+})=+51 kJ mol−1^{-1}.

Answer: 51