JEE Main 2022 · 27 Jun · Shift 2 · Chemistry Q76

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ChemistrySingle correct+4 / -1Question 76 of 90

Decarboxylation of all six possible forms of diaminobenzoic acids $\mathrm{C_6H_3(NH_2)_2COOH}$ yields three products A, B and C. Three acids give a product 'A', two acids gives a product 'B' and one acid give a product 'C'. The melting point of product 'C' is

63°C

90°C

104°C

142°C

Answer and worked solution

Official answer: D

Products. Losing COOH turns each acid into a phenylenediamine. Of the six acids (NH₂ at 2,3; 2,4; 2,5; 2,6; 3,4; 3,5), three give the meta, two the ortho and one (2,5) the para isomer.

C is p-phenylenediamine, m.p. about 142 °C.

(D)

Topics:Amines Structural isomerism

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JEE Main 2022 · 27 Jun · Shift 2, Chemistry question 76