Skip to content
dronacharya.ai
← JEE Main 2022 · 27 Jun · Shift 1
PhysicsInteger+4 / -1Question 60 of 90

JEE Main 2022 · 27 Jun · Shift 1, Physics question 60

A pendulum of length 2 m consists of a wooden bob of mass 50 g. A bullet of mass 75 g is fired towards the stationary bob with a speed vv. The bullet emerges out of the bob with a speed v3\dfrac v3 and the bob just completes the vertical circle. The value of vv is ______ ms−1^{-1}. (if g=10g=10 m/s2^2).

Answer and worked solution

Official answer: 10

Bob just completes the circle. It needs 5gl=10\sqrt{5gl}=10 m/s at the bottom.

Momentum. 0.075v=0.075v3+0.05×100.075v=0.075\frac v3+0.05\times10, so 0.05v=0.50.05v=0.5 and v=10v=10 m/s.

Answer: 10