JEE Main 2022 · 27 Jun · Shift 1 · Physics Q57

← JEE Main 2022 · 27 Jun · Shift 1

PhysicsInteger+4 / -1Question 57 of 90

A capacitor of capacitance 50 pF is charged by 100 V source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss in the process is ______ nJ.

Your answer

Answer and worked solution

Official answer: 125

Sharing with an identical capacitor loses half the energy: $\frac14CV^2=\frac14\times50\times10^{-12}\times10^4=125$ nJ.

Answer: 125

Topics:Energy stored in a capacitor

← Previous question Next question →

JEE Main 2022 · 27 Jun · Shift 1, Physics question 57