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← JEE Main 2022 · 27 Jun · Shift 1
PhysicsInteger+4 / -1Question 54 of 90

JEE Main 2022 · 27 Jun · Shift 1, Physics question 54

A beam of monochromatic light is used to excite the electron in Li++\mathrm{Li^{++}} from the first orbit to the third orbit. The wavelength of monochromatic light is found to be x×10−10x\times10^{-10} m. The value of xx is ______.

[Given hc=1242hc=1242 eV nm]

Answer and worked solution

Official answer: 114

Energy for Li2+\mathrm{Li^{2+}} (Z=3Z=3), 1 → 3: 13.6×9(1−19)=108.813.6\times9\left(1-\frac19\right)=108.8 eV.

Wavelength. 1242108.8≈11.4\frac{1242}{108.8}\approx11.4 nm =114×10−10=114\times10^{-10} m.

Answer: 114