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← JEE Main 2022 · 27 Jun · Shift 1
MathematicsInteger+4 / -1Question 22 of 90

JEE Main 2022 · 27 Jun · Shift 1, Mathematics question 22

If the sum of all the roots of the equation e2x−11ex−45e−x+812=0e^{2x}-11e^x-45e^{-x}+\dfrac{81}2=0 is log⁡ep\log_ep, then pp is equal to ______.

Answer and worked solution

Official answer: 45

Cubic in t=ext=e^x. Multiplying by exe^x: 2t3−22t2+81t−90=02t^3-22t^2+81t-90=0.

Keyed reasoning. Treating all three roots, t1t2t3=45t_1t_2t_3=45, so ∑x=log⁡e45\sum x=\log_e45 and p=45p=45.

Note. t=2t=2 is a root and the other factor 2t2−18t+452t^2-18t+45 has no real roots, so the only real root is x=log⁡e2x=\log_e2. The key's 45 counts the complex roots too.

Answer: 45