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← JEE Main 2022 · 27 Jun · Shift 1
MathematicsSingle correct+4 / -1Question 3 of 90

JEE Main 2022 · 27 Jun · Shift 1, Mathematics question 3

If x=∑n=0∞anx=\displaystyle\sum_{n=0}^\infty a^n, y=∑n=0∞bny=\displaystyle\sum_{n=0}^\infty b^n, z=∑n=0∞cnz=\displaystyle\sum_{n=0}^\infty c^n, where a,b,ca,b,c are in A.P. and ∣a∣<1|a|<1, ∣b∣<1|b|<1, ∣c∣<1|c|<1, abc≠0abc\ne0, then :

Choose one option
Answer and worked solution

Official answer: C

Sums. x=11−ax=\dfrac1{1-a}, so 1x=1−a\dfrac1x=1-a; likewise 1y=1−b\dfrac1y=1-b, 1z=1−c\dfrac1z=1-c.

A.P. a,b,ca,b,c in A.P. makes 1−a,1−b,1−c1-a,1-b,1-c an A.P.

(C)