JEE Main 2022 · 27 Jun · Shift 1 · Chemistry Q84

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ChemistryInteger+4 / -1Question 84 of 90

$\mathrm{2NOCl(g)\rightleftharpoons2NO(g)+Cl_2(g)}$
In an experiment, 2.0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0.4 mol/L. The equilibrium constant at 30°C is ______ $\times10^{-4}$ .

Your answer

Answer and worked solution

Official answer: 125

Equilibrium. NO 0.4, so NOCl $2.0-0.4=1.6$ and $\mathrm{Cl_2}$ 0.2 mol/L.

Constant. $K=\dfrac{(0.4)^2(0.2)}{(1.6)^2}=0.0125=125\times10^{-4}$ .

Answer: 125

Topics:Law of mass action and Kc, Kp

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JEE Main 2022 · 27 Jun · Shift 1, Chemistry question 84