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← JEE Main 2022 · 27 Jun · Shift 1
ChemistryInteger+4 / -1Question 82 of 90

JEE Main 2022 · 27 Jun · Shift 1, Chemistry question 82

If the uncertainty in velocity and position of a minute particle in space are, 2.4×10−262.4\times10^{-26} (m s−1^{-1}) and 10−710^{-7} (m) respectively. The mass of the particle in g is ______. (Nearest integer)

(Given : h=6.626×10−34h=6.626\times10^{-34} Js)

Answer and worked solution

Official answer: 22

Uncertainty principle. m=h4π Δx Δv=6.626×10−344π×10−7×2.4×10−26≈0.022m=\dfrac h{4\pi\,\Delta x\,\Delta v}=\dfrac{6.626\times10^{-34}}{4\pi\times10^{-7}\times2.4\times10^{-26}}\approx0.022 kg =22=22 g.

Answer: 22