Skip to content
dronacharya.ai
← JEE Main 2022 · 26 Jun · Shift 2
PhysicsSingle correct+4 / -1Question 44 of 90

JEE Main 2022 · 26 Jun · Shift 2, Physics question 44

A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s−1^{-1}. If the horizontal component of earth's magnetic field is 0.2×10−40.2\times10^{-4} T, then emf induced between the two ends of the conductor is :

Choose one option
Answer and worked solution

Official answer: B

Geometry. Rotating in a vertical east-west plane, the rod's plane is perpendicular to the horizontal (north-south) field.

emf. 12Bωl2=12(0.2×10−4)(5)(1)2=5×10−5\frac12B\omega l^2=\frac12(0.2\times10^{-4})(5)(1)^2=5\times10^{-5} V =50 μ=50\ \muV.

(B)

Topics:Motional EMFEarth's magnetism
← Previous questionNext question →