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← JEE Main 2022 · 26 Jun · Shift 2
ChemistryInteger+4 / -1Question 90 of 90

JEE Main 2022 · 26 Jun · Shift 2, Chemistry question 90

The moles of methane required to produce 81 g of water after complete combustion is ______ ×10−2\times10^{-2} mol. [nearest integer]

Answer and worked solution

Official answer: 225

Water. 8118=4.5\frac{81}{18}=4.5 mol; each CH4\mathrm{CH_4} gives 2 H2O\mathrm{H_2O}.

Methane 2.252.25 mol =225×10−2=225\times10^{-2}.

Answer: 225