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← JEE Main 2022 · 26 Jun · Shift 2
ChemistryInteger+4 / -1Question 88 of 90

JEE Main 2022 · 26 Jun · Shift 2, Chemistry question 88

Catalyst A reduces the activation energy for a reaction by 10 kJ mol−1^{-1} at 300 K. The ratio of rate constants, kT,CatalysedkT,Uncatalysed\dfrac{k_{T,\text{Catalysed}}}{k_{T,\text{Uncatalysed}}} is exe^x. The value of xx is ______. [nearest integer]

[Assume that the pre-exponential factor is same in both the cases. Given R=8.31R=8.31 J K−1^{-1}mol−1^{-1}]

Answer and worked solution

Official answer: 4

Arrhenius ratio. ln⁡kcatk=ΔEaRT=100008.31×300≈4.01\ln\dfrac{k_{\rm cat}}{k}=\dfrac{\Delta E_a}{RT}=\dfrac{10000}{8.31\times300}\approx4.01.

Answer: 4